Pinball_NL
Pinball_NL
·Posted in ctrlX DRIVE

MSM motor inertia. What are the exact values I have to use ?

I have selected the MS2M as a replacement for the MSM. In the MSM Manual they mention the rotor inertia and separate the brake inertia. These values are exact the same as the MS2M. I think the total inertia will be the rotor inertia + the brake inertia.

However, in the MS2M I see another value or a different approach.

Why is this (17) stated in the manual Jrot = 0,000014(17) ? *

() = with holding brake

Here you find the MS2M03-A. Motor Inertia of 0,14 kg.cm2 and with brake 0,17 kg.cm2

But a little under you see the exact inertia of the brake. This is 0,018 kg.cm2

So I say the inertia will be 0,14 + 0,018 = 0,158 kg.cm2. (and not 0,170 kg.cm2)

Is there more inertia involved? Maybe a longer axis or a component I do not know. I like to know what the right inertia is. I'm prety sure this MSM and MS2M have the same inertia. But is it 0,158 of 0,170.

If it has 0,170 kg.cm2 then it has 7,5 % more inertia as I expected.

Best reply by macmotor

0.000014 and 0.000014 kg*m² are the correct values for the rotor inertia of this MS2M03-A, as indicated in the manual.

The 0.0000018 kg*m² is the value of the rotary part of the brake alone, but not including fixture parts, different shaft dimensions etc. This value for itself is correct too, but not relevant for sizing etc., thus it does not really make sense to indicate it in the manual. The writers team will be noted.

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